tag:blogger.com,1999:blog-10220498.post1313271478499563788..comments2022-01-20T19:15:12.121-06:00Comments on Math Teacher Mambo: Fun ProblemsShireen Dadmehrhttp://www.blogger.com/profile/16282965851939089408noreply@blogger.comBlogger5125tag:blogger.com,1999:blog-10220498.post-34598072948701850632011-06-23T06:31:31.888-05:002011-06-23T06:31:31.888-05:00Gasstationwithoutpumps: hmmmmm, I guess I could re...Gasstationwithoutpumps: hmmmmm, I guess I could refine it as "cutting the cake from the top down in a "normal" fashion. I'd have to think about the precision of words.<br /><br />Mr. H: Thanks for another fun resource of brain candy.Shireen Dadmehrhttps://www.blogger.com/profile/16282965851939089408noreply@blogger.comtag:blogger.com,1999:blog-10220498.post-92063519756838281462011-06-22T23:18:43.066-05:002011-06-22T23:18:43.066-05:00You might like Wu Riddles. Some of the easier puzz...You might like <a href="http://wuriddles.com/" rel="nofollow">Wu Riddles</a>. Some of the easier puzzles I give to my students after tests.Mr. Hhttps://www.blogger.com/profile/12620847580362451503noreply@blogger.comtag:blogger.com,1999:blog-10220498.post-23816604407499582122011-06-21T13:08:04.406-05:002011-06-21T13:08:04.406-05:00"Square cake" is not informative enough,..."Square cake" is not informative enough, as it does not give the height. For height 0, the problem is trivial (just 5 rectangular slices of the top).<br /><br />For a cube, there is another easy, but tricky solution. Each frosted face has 1/5th of the icing, so let's cut in diagonally from the 8 frosted edges, making a pyramid for the top face and truncated triangular wedges for the side faces. All you need to figure out is how tall to make the pyramid to have 1/5 the volume of the cube. As long as that is less than the height of the cube you're set. Since the volume of a pyramid is 1/3 base area times height, the depth of the top piece at the center needs to be 3/5 of the side length.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-10220498.post-41481978275628509012011-06-20T22:08:38.324-05:002011-06-20T22:08:38.324-05:00Oh! Thank You! These look uber fun. Now I'm go...Oh! Thank You! These look uber fun. Now I'm going away to churn on the "petal" problem .....Shireen Dadmehrhttps://www.blogger.com/profile/16282965851939089408noreply@blogger.comtag:blogger.com,1999:blog-10220498.post-37330767536705052432011-06-20T21:49:34.164-05:002011-06-20T21:49:34.164-05:00There are some fascinating problems at risps.co.uk...There are some fascinating problems at risps.co.uk, and <a href="http://mathteacherorstudent.blogspot.com/2011/05/teaching-problem-solving-part-2-some.html" rel="nofollow">these problems</a> at Avery's blog are cool. Back in April I posted about this problem:<br /><br /><br /> My favorite candy come in packages of 5 or 6. What's the largest number for which I cannot buy exactly that many candies? Can this be generalized? <br /><br />And I loved <a href="http://mathmamawrites.blogspot.com/2011/04/book-review-rediscovering-mathematics.html" rel="nofollow">this problem</a>.<br /><br />That should be enough to keep you out of trouble for a while. ;^)Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.com